为什么用FOR循环取余数码管显示就不正常呢

ID:505859 · 发表于 2019-4-6 17:54

#include<reg52.h>
sbit LA=P2^2;
sbit LB=P2^3;
sbit LC=P2^4;
unsigned char code smguan[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,
      0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
unsigned char Ledbuf[6]={0x00,0x00,0x00,0x00,0x00,0x00};
unsigned int counter=0;
unsigned char buf[6];
unsigned int stopwatch=65000;

void T1_Timer();
void main(void)
{



   unsigned char i=0;
   T1_Timer();
while(1)
{

   if(counter==1000)
   {
   counter=0;
   stopwatch--;
   for(i=0;i<6;i++)
      {
buf[i]=stopwatch%10;
   stopwatch /=10;
      }
   }
}
}

void T1_Timer()
{
   TMOD=0X01;
   TH0=0XFC;
   TL0=0X18;
   TR0=1;
   EA=1;
   ET0=1;

}

void Keyscan()
{
   static unsigned char i=0;
   P0=0X00;
   switch(i)
   {
   case 0: LA=0;LB=0;LC=0;break;
   case 1: LA=1;LB=0;LC=0;break;
   case 2: LA=0;LB=1;LC=0;break;
   case 3: LA=1;LB=1;LC=0;break;
   case 4: LA=0;LB=0;LC=1;break;
   case 5: LA=1;LB=0;LC=1;break;
   case 6: LA=0;LB=1;LC=1;break;
   case 7: LA=1;LB=1;LC=1;break;
   default:break;

   }
   P0=smguan[buf[i]];
   i++;
      if(i==8)i=0;
}

void interrupt_Timter1() interrupt 1
{

   TH0=0XFC;
      TL0=0X18;
   counter++;
   Keyscan();
}

ID:164602 · 发表于 2019-4-6 22:09

是你的程序问题，与for无关
给你改好了，试试看
#include<reg52.h>
sbit LA=P2^2;
sbit LB=P2^3;
sbit LC=P2^4;
unsigned char code smguan[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,
                                          0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
unsigned char Ledbuf[6]={0x00,0x00,0x00,0x00,0x00,0x00};
unsigned int counter=0;
unsigned char buf[6];
unsigned int stopwatch=12345,ST;

void T1_Timer();
void main(void)
{



      unsigned char i=0;
      T1_Timer();
      while(1)
      {

   ST=stopwatch;
               if(counter>=1000)
               {
                              counter=0;
                              stopwatch--;
                              for(i=0;i<6;i++)
                                          {
                                                      buf[i]=ST%10;
                                                      ST /=10;
                                          }
               }
      }
}

void T1_Timer()
{
      TMOD=0X01;
      TH0=0Xfc;
      TL0=0X18;
      TR0=1;
      EA=1;
      ET0=1;

}

void Keyscan()
{
      static unsigned char j=0;
      P0=0X00;
      switch(j)
      {
               case 0: LA=0;LB=0;LC=0;break;
               case 1: LA=1;LB=0;LC=0;break;
               case 2: LA=0;LB=1;LC=0;break;
               case 3: LA=1;LB=1;LC=0;break;
               case 4: LA=0;LB=0;LC=1;break;
               case 5: LA=1;LB=0;LC=1;break;
               case 6: LA=0;LB=1;LC=1;break;
               case 7: LA=1;LB=1;LC=1;break;
               default:break;

      }
         P0=smguan[buf[j]];
               j++;
         if(j==8)j=0;
}

void interrupt_Timter1() interrupt 1
{

               TH0=0Xfc;
            TL0=0X18;
               counter++;
               Keyscan();
}

ID:213173 · 发表于 2019-4-6 22:43

你这样处理只循环1次stopwatch就面目全非了，需要加一个临时变量过渡才不会破坏stopwatch。
void main(void)
{
unsigned char i=0;
unsigned int count;
T1_Timer();
while(1)
{
if(counter==1000)
{
counter=0;
stopwatch--;
count=stopwatch;
for(i=0;i<6;i++)
{
buf[i]=count%10;
count/=10;
}
}
}
}

ID:505859 · 发表于 2019-4-7 08:33

wulin 发表于 2019-4-6 22:43
你这样处理只循环1次stopwatch就面目全非了，需要加一个临时变量过渡才不会破坏stopwatch。
void main(voi ...

好的，谢谢

ID:505859 · 发表于 2019-4-7 08:33

HC6800-ES-V2.0 发表于 2019-4-6 22:09
是你的程序问题，与for无关
给你改好了，试试看
#include

好了，谢谢！

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