这段单片机程序24C02存放一个值并读出显示在lcd1602上，为什么不对?

ID:405225 · 发表于 2019-5-4 19:27

#include<reg52.h>
#define unint unsigned int
#define uchar unsigned char
sbit sda=P3^4;
sbit scl=P3^3;
sbit rs=P2^0;
sbit rw=P2^1;
sbit en=P2^2;
void delay(){;;}
void delayms(unint z)
{unint i,j;
for(i=z;i>0;i--)
  for(j=110;j>0;j--);
}
void init_24c02()
{
sda=1;
delay();
scl=1;
delay();
}
void start()
{
sda=1;
delay();
scl=1;
delay();
sda=0;
delay();
}
void stop()
{
sda=0;
delay();
scl=1;
delay();
sda=1;
delay();
}
void respons()
{
uchar i;
scl=1;
delay();
while((sda==1)&&(i<255))
i++;
scl=0;
delay();
}
void write_byte(uchar date)
{
uchar i,temp;
temp=date;
for(i=0;i<8;i++)
{ temp<<=1;
  scl=0;
  delay();
  sda=CY;
  delay();
  scl=1;
  delay();
}
scl=0;
delay();
sda=1;
delay();
}
uchar read_byte(void)
{
uchar i,j;
scl=0;
delay();
sda=1;
for(i=0;i<8;i++)
{
  scl=1;
  delay();
  j=(j<<1)|sda;
  scl=0;
  delay();
}
delay();
return j;
}
void write_add(uchar address,uchar date)
{
start();
write_byte(0xa0);
respons();
write_byte(address);
respons();
write_byte(date);
respons();
stop();
}
uchar read_add(uchar address)
{
uchar date;
start();
write_byte(0xa0);
respons();
write_byte(address);
respons();
start();
write_byte(0xa1);
respons();
date=read_byte();
stop();
return date;
}
void write_com(uchar com)
{en=0;
rs=0;
rw=0;
P0=com;
delayms(5);
en=1;
delayms(5);
en=0;
}
void write_data(uchar dat)
{en=0;
rs=1;
rw=0;
P0=dat;
delayms(5);
en=1;
delayms(5);
en=0;
}
void init_lcd1602()
{
en=1;
write_com(0x38);
write_com(0x0c);
write_com(0x06);
write_com(0x80);
write_com(0x01);
}
void main()
{uchar a;
init_24c02();
init_lcd1602();
write_data(0x30+8);
delayms(5);
write_add(1,8);
a=read_add(1);
write_com(0x40);
delayms(5);
write_data(0x30+a);
delayms(5);
while(1);
}

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