单片机程序错误就是看不懂哪里错了,提示syntax error语法错误

ID:627982 · 发表于 2019-11-2 18:27

总是提示这个括号有错误，如果我只有三个加法按键程序就没有问题，但是我加了减法按键就提示错误。希望大佬看一下找一下错误。这个程序是按键加法减法数码管显示。

#include <reg52.h>
sbit ADDR0 = P1^0;
sbit ADDR1 = P1^1;
sbit ADDR2 = P1^2;
sbit ADDR3 = P1^3;
sbit ENLED = P1^4;
sbit KEY_IN_1  = P2^4;
sbit KEY_IN_2  = P2^5;
sbit KEY_IN_3  = P2^6;
sbit KEY_IN_4  = P2^7;
sbit KEY_OUT_1 = P2^3;
sbit KEY_OUT_2 = P2^2;
sbit KEY_OUT_3 = P2^1;
sbit KEY_OUT_4 = P2^0;
unsigned char code LedChar[] = {
0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8,
0x80, 0x90, 0x88, 0x83, 0xC6, 0xA1, 0x86, 0x8E
};
unsigned char LedBuff[6] = {
0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF
};
unsigned char code KeyCodeMap[4][4] = {
{ 0x31, 0x32, 0x33, 0x26 },
{ 0x34, 0x35, 0x36, 0x25 },
{ 0x37, 0x38, 0x39, 0x28 },
{ 0x30, 0x1B, 0x0D, 0x27 }
};
unsigned char KeySta[4][4] = {
{1, 1, 1, 1},  {1, 1, 1, 1},  {1, 1, 1, 1},  {1, 1, 1, 1}
};
void KeyDriver();
void main()
{
EA = 1;
ENLED = 0;
ADDR3 = 1;
TMOD = 0x01;
TH0  = 0xFC;
TL0  = 0x67;
ET0  = 1;
TR0  = 1;
LedBuff[3] = LedChar[0];
         LedBuff[0] = LedChar[0];
while (1)
{
      KeyDriver();
}
}
void KeyAction(unsigned char keycode)
{
         static unsigned char A = 0;
         static unsigned char B = 0;
         static unsigned char C = 0;
         static unsigned char D = 0;
         static unsigned char E = 0;
         static unsigned char F = 0;
         static unsigned char G = 0;
         static unsigned char H = 0;
         static unsigned char M = 0;
         static unsigned char K = 0;

         if((keycode==0x31)|(keycode==0x32)|(keycode==0x33)|(keycode==0x26))
         {
                     if(keycode==0x31)
                              {
                                       A=A+1;
                              }
                                                   if(keycode==0x32)
                              {
                                       B=B+2;
                              }
                                                   if(keycode==0x33)
                              {
                                       C=C+3;
                              }
                              if(keycode==0x26)
                              {
                                       D=D-1;
                              }
                              E=A+B+C;
                              LedBuff[0] = LedChar[G%10];
                              LedBuff[1] = LedChar[G/10%10];
                              LedBuff[2] = LedChar[G/100%10];
                  }
                  else if((keycode==0x34)|(keycode==0x35)|(keycode==0x36)|(keycode==0x25)
         {
                     if(keycode==0x34)
                              {
                                       F=F+1;
                              }
                              if(keycode==0x35)
                              {
                                       G=G+2;
                              }
                              if(keycode==0x36)
                              {
                                       H=H+3;
                              }
                              if(keycode==0x25)

                              M=F+G+H;
                              LedBuff[3] = LedChar[H%10];
                              LedBuff[4] = LedChar[H/10%10];
                              LedBuff[5] = LedChar[H/100%10];//êy??1ü??ê?????
                  }

                  if(keycode==0x1b)
                  {
                              A=0;B=0;C=0;D=0;E=0;F=0;G=0;H=0;K=0;M=0;
                              LedBuff[0] = LedChar[0];
                              LedBuff[1] = LedChar[0];
                              LedBuff[2] = LedChar[0];
                              LedBuff[3] = LedChar[0];
                              LedBuff[4] = LedChar[0];
                              LedBuff[5] = LedChar[0];
                  }//??á?′|àí

}
void KeyDriver()
{
unsigned char i, j;
static unsigned char backup[4][4] = {
      {1, 1, 1, 1},  {1, 1, 1, 1},  {1, 1, 1, 1},  {1, 1, 1, 1}
};

for (i=0; i<4; i++)
{
      for (j=0; j<4; j++)
      {
         if (backup[ i][j] != KeySta[ i][j])
         {             if (backup[ i][j] != 0)
            {
                  KeyAction(KeyCodeMap[ i][j]);
            }
            backup[ i][j] = KeySta[ i][j];
         }
      }
}
}
void KeyScan()
{
unsigned char i;
static unsigned char keyout = 0;
static unsigned char keybuf[4][4] = {
      {0xFF, 0xFF, 0xFF, 0xFF},  {0xFF, 0xFF, 0xFF, 0xFF},
      {0xFF, 0xFF, 0xFF, 0xFF},  {0xFF, 0xFF, 0xFF, 0xFF}
};


keybuf[keyout][0] = (keybuf[keyout][0] << 1) | KEY_IN_1;
keybuf[keyout][1] = (keybuf[keyout][1] << 1) | KEY_IN_2;
keybuf[keyout][2] = (keybuf[keyout][2] << 1) | KEY_IN_3;
keybuf[keyout][3] = (keybuf[keyout][3] << 1) | KEY_IN_4;

for (i=0; i<4; i++)
{
      if ((keybuf[keyout][ i] & 0x0F) == 0x00)
      { //á?D?4′?é¨?è?μ?a0￡??′4*4ms?ú??ê?°′??×′ì?ê±￡??éè??a°′?üò??è?¨μ?°′??
         KeySta[keyout][ i] = 0;
      }
      else if ((keybuf[keyout][ i] & 0x0F) == 0x0F)
      {
         KeySta[keyout][ i] = 1;
      }
}

keyout++;
keyout = keyout & 0x03;
switch (keyout)
{
      case 0: KEY_OUT_4 = 1; KEY_OUT_1 = 0; break;
      case 1: KEY_OUT_1 = 1; KEY_OUT_2 = 0; break;
      case 2: KEY_OUT_2 = 1; KEY_OUT_3 = 0; break;
      case 3: KEY_OUT_3 = 1; KEY_OUT_4 = 0; break;
      default: break;
}
}
void LedScan()
{
static unsigned char i = 0;

P0 = 0xFF;
switch (i)
{
      case 0: ADDR2=0; ADDR1=0; ADDR0=0; i++; P0=LedBuff[0]; break;
      case 1: ADDR2=0; ADDR1=0; ADDR0=1; i++; P0=LedBuff[1]; break;
      case 2: ADDR2=0; ADDR1=1; ADDR0=0; i++; P0=LedBuff[2]; break;
      case 3: ADDR2=0; ADDR1=1; ADDR0=1; i++; P0=LedBuff[3]; break;
      case 4: ADDR2=1; ADDR1=0; ADDR0=0; i++; P0=LedBuff[4]; break;
      case 5: ADDR2=1; ADDR1=0; ADDR0=1; i=0; P0=LedBuff[5]; break;
      default: break;
}
}
void InterruptTimer0() interrupt 1
{
TH0 = 0xFC;
TL0 = 0x67;
LedScan();
KeyScan();
}

ID:627982 · 发表于 2019-11-2 18:33

错误在else if(keycode==0x34)|(keycode==0x35）下的那个中括号，提示syntax error语法错误

ID:88256 · 发表于 2019-11-2 20:01

if括号需要配对，你的这句最后面就没有反括号
else if((keycode==0x34)|(keycode==0x35)|(keycode==0x36)|(keycode==0x25)

ID:632603 · 发表于 2019-11-2 20:41

for (i=0; i<4; i++)
{
      for (j=0; j<4; j++)
      {
         if (backup[ i][j] != KeySta[ i][j])
         {             if (backup[ i][j] != 0)
            {
                  KeyAction(KeyCodeMap[ i][j]);
            }
            backup[ i][j] = KeySta[ i][j];
         }
      }
}
} 其中的感叹号!！用了中文感叹号

ID:511890 · 发表于 2019-11-3 01:08

else if((keycode==0x34)|(keycode==0x35)|(keycode==0x36)|(keycode==0x25)这里少了个“）”，一般这种错误只要点击错误提示就会跳到这里(有的编译器会有误差，但是差不多就是在出错的语句前后)，然后纤细检查下语法就能发现错误。好的编译器可能还会提升少了一个“）”。不过是英文的。

ID:437615 · 发表于 2019-11-3 08:01

地板说的对,你这个程序少了个括号

ID:627982 · 发表于 2019-11-3 16:19

hhdsdy 发表于 2019-11-2 20:01
if括号需要配对，你的这句最后面就没有反括号
else if((keycode==0x34)|(keycode==0x35)|(keycode==0x36)| ...

感谢，就是这里

ID:627982 · 发表于 2019-11-3 16:21

幻剑心发表于 2019-11-3 01:08
else if((keycode==0x34)|(keycode==0x35)|(keycode==0x36)|(keycode==0x25)这里少了个“）”，一般这种错 ...

谢谢，就是这里

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