单片机可调电子时钟想加一个蜂鸣器求方法

ID:770620 · 发表于 2020-6-14 12:05

上面是加了蜂鸣器的电路图

实验的要求是：

目前前三点已经可以通过下面的编程达到要求，第四点，我在电路图上加了蜂鸣器，但是不会写程序，急！！！！！！

编程：#include <reg51.h>
#define uchar unsigned char
#define uint unsigned int
sbit set=P1^0;
sbit save=P1^5;
sbit rselect=P1^1;
sbit lselect=P1^2;
sbit add=P1^3;
sbit reduce=P1^4;
uchar code tab[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f};
uchar disp_buf[6];
uchar disp_bit=0;
uint hour,min,sec;
uint select_num=0;
uint hour_adj,min_adj,sec_adj;
uchar count;
uchar key_num=0;
void key_scan()
{
if(!set)
{
  hour_adj=hour;
  min_adj=min;
  sec_adj=sec;
  key_num++;
}
while(!set);
if(key_num%2==1)
{
  if(rselect==0)
  {
select_num++;
if(select_num==4)
select_num=1;
  }
  while(!rselect);
  if(lselect==0)
  {
select_num--;
if(select_num<=0)
select_num=3;
  }
  while(!lselect);
}
if(!add&&(key_num%2))
{
  switch(select_num)
  {
case 1 :
{
hour_adj++;
if(hour_adj==24)
hour_adj=0;
break;
}
case 2 :
{
min_adj++;
if(min_adj==60)
min_adj=0;
break;
}
case 3 :
{
sec_adj++;
if(sec_adj==60)
sec_adj=0;
break;
}
default:break;
  }
  while(!add);
}
if(!reduce&&(key_num%2))
{
  switch(select_num)
  {
case 1 :
{
hour_adj--;
if(hour_adj<=0)
hour_adj=23;
break;
}
case 2 :
{
min_adj--;
if(min_adj<=0)
min_adj=59;
break;
}
case 3 :
{
sec_adj--;
if(sec_adj<=0)
sec_adj=59;
break;
}
default:break;
  }
  while(!reduce);
}
if(!save&&(key_num%2))
{
  select_num=0;
  hour=hour_adj;
  min=min_adj;
  sec=sec_adj;
  while(!save);
}
}

/*Ö÷º¯Êý*/
void main()
{
TMOD=0x11;
TH0=0xf7;
TL0=0x00;
TH1=0x4c;
TH0=0x00;
ET0=1;
ET1=1;
EA=1;
TR0=1;
TR1=1;
PT1=1;
hour=20;
min=02;
sec=07;
count=0;
while(1)
{
  key_scan();
  if(key_num%2)
  {
  switch(select_num)
  {
case 1 :
{
   if(count<=10)
{
   disp_buf[0]=hour_adj/10;
   disp_buf[1]=hour_adj%10;
}
else
{
   disp_buf[0]=0x40;
   disp_buf[1]=0x40;
}
disp_buf[2]=min_adj/10;
disp_buf[3]=min_adj%10;
disp_buf[4]=sec_adj/10;
disp_buf[5]=sec_adj%10;
break;
}
case 2 :
{
   if(count<=10)
{
   disp_buf[2]=min_adj/10;
   disp_buf[3]=min_adj%10;
}
else
{
   disp_buf[2]=0x40;
   disp_buf[3]=0x40;
}
disp_buf[0]=hour_adj/10;
disp_buf[1]=hour_adj%10;
disp_buf[4]=sec_adj/10;
disp_buf[5]=sec_adj%10;
break;
}
case 3 :
{
   if(count<=10)
{
   disp_buf[4]=sec_adj/10;
   disp_buf[5]=sec_adj%10;
}
else
{
   disp_buf[4]=0x40;
   disp_buf[5]=0x40;
}
disp_buf[0]=hour_adj/10;
disp_buf[1]=hour_adj%10;
disp_buf[2]=min_adj/10;
disp_buf[3]=min_adj%10;
break;
}
default :  break;
  }
  }
  if(key_num%2==0)
  {
disp_buf[0]=hour/10;
disp_buf[1]=hour%10;
disp_buf[2]=min/10;
disp_buf[3]=min%10;
disp_buf[4]=sec/10;
disp_buf[5]=sec%10;

  }
}
}

void timer0() interrupt 1
{
TH0=0xf7;
TL0=0x00;
P2=~(0x01<<disp_bit);
P0=tab[disp_buf[disp_bit]];
disp_bit++;
if(disp_bit==6) disp_bit=0;
}
void timer1() interrupt 3
{
TH1=0x4c;
TL1=0x00;
if(++count==20)
{
  count=0;
  if(++sec==60)
  {
sec=0;
if(++min==60)
{
min=0;
if(++hour==24)
{
   hour=0;
      }
}
  }
}
}