通过I2C通信实现AT024的储存读取利用51单片机C语言完成

ID:864860 · 发表于 2021-1-25 15:28

#include<reg52.h>
#include<intrins.h>
#define uchar unsigned char
sbit  duan=P2^6;
sbit  wei=P2^7 ;
sbit  SDA=P2^0;
sbit  SCL=P2^1;
bit flag;
int index=0;
uchar s;
uchar code duanS[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f};
uchar code weiS[]={0xef,0xdf,0xbf};

void delay5us(){
_nop_();
_nop_();
_nop_();
_nop_();
}
void i2cStart(){
   SCL=1;
   SDA=0; //高变低【有效】
   SDA=1;
   delay5us();
   SDA=0;
   delay5us();
   SCL=0;
}
void i2cEnd(){
   SCL=0;
   SDA=0;
   SCL=1;
   delay5us();
   SDA=1;
   delay5us();
}

bit i2cAck(){    //我觉得可以用来阻塞或者反复传操作
SCL=1;
delay5us();
if(SDA) {
SCL=0;
return(1);
}
else {
SCL=0;
return(0);
}
}
void i2cSendAck(bit b)
{
  SCL=0;
  if(b)
    SDA=1;
  else
    SDA=0;
  SCL=1;
  delay5us();
  SCL=0;
  SDA=1;
}
void send(uchar DATA){
   uchar i;
   for(i=0;i<8;i++){
      SCL=0;
   if (DATA & 0x80)
     SDA=1;
   else
     SDA=0;
   SCL=1;
   delay5us();
   DATA<<=1;
}
SCL=0;
SDA=1;
}
void i2cSend(uchar dataddr ,uchar dat){
i2cStart();
send(0xA0);
   if(i2cAck())
flag=1;
else flag=0;

send(dataddr);
if(i2cAck())
flag=1;
else flag=0;

send(dat);
if(i2cAck())
flag=1;
else flag=0;
i2cEnd();
}
uchar accpect(){
uchar i,index1;
   for(i=0;i<8;i++){
   index1<<=1;
   SCL=0;
   SCL=1;
   delay5us();
   if(SDA)
   index1|=0X01;
}
return index1;
}
uchar i2cAccp(uchar dataddr){
uchar index1;
i2cStart();
send(0xA0);
if(i2cAck())
flag=1;
else flag=0;
send(dataddr);
i2cAck();

i2cStart();
send(0xA1);
if(i2cAck())
flag=1;
else
flag=0;
// for(i=0;i<8;i++){
//    index1<<=1;
//    SCL=0;
//    SCL=1;
//    delay5us();
//    if(SDA)
//    index1|=0X01;
//}
index1=accpect();
i2cSendAck(1);
i2cEnd();
return index1;
}
void initP3(){
   EA=1;
   ET1=1;
   TR1=1;
   TMOD=0x10;
   TH1=60927/255;
   TL1=60927%255;
}

void display(uchar i){
P0=weiS[index];
switch(index) {
   case 0: wei=1;duan=0;wei=0;duan=1;P0=duanS[i/100];
   break;
   case 1: wei=1;duan=0;wei=0;duan=1;P0=duanS[i/10%10];
   break;
   case 2: wei=1;duan=0;wei=0;duan=1;P0=duanS[i%10];
   break;
}
index++;
if(index>=3)
index=0;

}
void main(){
   uchar i=1000;
   initP3();
   i2cSend(3,236);
   while(i--);
   s=i2cAccp(3);
   while(1);
}
void interP3() interrupt 3{
TH1=60927/255;
TL1=60927%255;
display(s);
}

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