GP2Y02A21传感器在单片机开发板测距显示程序如何修改才能使用?

ID:852397 · 发表于 2021-5-7 18:23

刚开始学单片机，简单的程序还能看看，复杂的就看不太懂。
现在需要红外测距通过这个开发板显示在1602屏幕上，在网上也搜了好多例程，都用不了，求大佬指点一下程序怎么改改才能使用。
谢谢

单片机源程序如下:
#include"reg52.h"
#include<intrins.h>
#define uint unsigned int
#define uchar unsigned char

sbit cs = P3^2;
long int read=0;
sbit wela = P2^7;
sbit dula = P2^6;
sbit lcden=P3^4;
sbit lcdrs=P3^5;

uchar bai,shi,ge,num;

uchar table[] ="123456789";

void delayms(uint z)
{
      uint x,y;
      for(x=z;x>0;x--)
            for(y=110;y>0;y-- );
}

void write_com(uchar com)
{
      lcdrs=0;
      P0=com;
      delayms(5);
      lcden=1;
      delayms(5);
      lcden=0;
}

void write_data(uchar date)
{
      lcdrs=1;
      P0=date;
      delayms(5);
      lcden=1;
      delayms(5);
      lcden=0;
}

void init()
{
      dula=0;
      wela=0;
      lcden=0;
      write_com(0x38);
      write_com(0x0c);
      write_com(0x06);
      write_com(0x01);
}
void delay(uint a)          //  a 个1us延时
{
      for(;a > 0;a --)
      _nop_();_nop_();
}

void T0_time() interrupt 1
{
      cs = 0;
      RD = 0;
      read = P1;
      INT0 = 1;
}
uint adc0804()
{
TMOD=0X01;
TH0=(65536-45872)/256;
TL0=(65536-45872)/256;
EA=1;
ET0=1;
TR0=1;

      INT0 = 1;
      cs = 0;
      WR = 0;
      delay(255);
      cs = 1;
      WR = 1;
      delay(200);
      read = read * 196 /100;
      return read;

}

void math(uint x)
{
      bai = x / 100;
      shi = x /10 % 10;
      ge = x % 10;
}
void display()
{

      math(adc0804());

      dula=1;
      P0 = table[bai+10];
      dula=0;
      P0=0xff;

      wela = 1;
      P0 = 0xfe;
      wela=0;
      delay(7000000);


      dula=1;
      P0 = table[shi];
      dula=0;
      P0=0xff;

      wela = 1;
      P0 = 0xfd;
      wela=0;
      delay(7000000);


      dula=1;
      P0 = table[ge];
      dula=0;
      P0=0xff;

      wela = 1;
      P0 = 0xfb;
      wela=0;
      delay(7000000);

}

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