8位LED数码管显示从0到9999 9999

ID:647261 · 发表于 2023-5-17 10:44

初学单片机，学到LED数码管显示的时候，发现个位数显示快，到了十位数及以上的时候，速度就慢下来了。
单纯调延时似乎不行，想要做成每次加1的速度都差不多时间，不知道这个该怎么解决？

原理图

#include <reg51.h>
#include <stdio.h>
#define uchar unsigned char
#define uint unsigned int
#define ulong unsigned long
sbit clk = P3^0;
sbit dat = P3^1;
sbit sclk1 = P3^2;
sbit sclk2 = P3^3;
uchar code num[] = {0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};

void delay100us(uint n)
{
uchar i;
for(;n>0;n--)
{
   for(i=0;i<10;i++){;}
}
}

void data_num(uchar dat8) //串口数据发送数字数据
{
uchar i;
for(i=0;i<8;i++)
{
   clk = 0;
   dat = (dat8 >> i) & 0x01;
   clk = 1;
}
sclk1 = 0;
sclk1 = 1;
}

void digit_num(uchar digit) //串口数据发送LED位数数据
{
uchar i;
for(i=0;i<8;i++)
{
   clk = 0;
   dat = (digit >> i) & 0x01;
   clk = 1;
}
sclk2 = 0;
sclk2 = 1;
}

int digit_check(ulong n) //检测显示目标数的位数
{
uchar m;
if(n>9999999)
m = 8;
else if(n>999999)
m = 7;
else if(n>99999)
m = 6;
else if(n>9999)
m = 5;
else if(n>999)
m = 4;
else if(n>99)
m = 3;
else if(n>9)
m = 2;
else
m = 1;
return m;
}

int main(void)
{
ulong i,n;
uint ii,j,m;
while(1)
{
   for(i=0;i<100000000;i++) //从0显示到9999 9999
   {
   for(ii=0;ii<30;ii++) //显示延时
   {
      m = digit_check(i);
      n = i;
      for(j=0;j<m;j++)
      {
         data_num(0xff);
         digit_num(0x01 << j);
         data_num(num[n%10]);
         delay100us(100);
         n = n/10;
      }
   }
   }
}
}

ID:94031 · 发表于 2023-5-17 14:05

显示数目递进不要用for,用定时间隔+1.

ID:213173 · 发表于 2023-5-17 15:02

#include <reg51.h>
//#include <stdio.h>
#define uchar unsigned char
#define uint unsigned int
#define ulong unsigned long
sbit clk = P3^0;
sbit dat = P3^1;
sbit sclk1 = P3^2;
//sbit sclk2 = P3^3;
uchar code num[] = {0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};
uchar data buf[8];
ulong n,m;
uchar i,k;
uint j;
void data_num(uchar dat8,digit) //串口数据发送数字数据
{
uchar i;
for(i=0;i<8;i++)
{
clk = 0;
dat = (dat8 >> i) & 0x01;
clk = 1;
}
for(i=0;i<8;i++)
{
clk = 0;
dat = (digit >> i) & 0x01;
clk = 1;
}
sclk1 = 0;
sclk1 = 1;
}
void InitTimer0(void)//@12MHz 1ms
{
TMOD = 0x01;
TH0 = 0x0FC;
TL0 = 0x18;
EA = 1;
ET0 = 1;
TR0 = 1;
}
int main(void)
{
InitTimer0();
while(1)
{
m=n;
for(i=0;i<8;i++)
{
buf[i]=m%10;
m/=10;
}
}
}
void Timer0Interrupt(void) interrupt 1
{
TH0 = 0xFC;
TL0 = 0x18;
j++;
if(j>=500)//500ms
{
j=0;
if(++n>99999999)
n=0;
}
data_num(0x01<<k,num[buf[k]]);
k=++k%8;
}

复制代码

ID:647261 · 发表于 2023-5-17 15:31

xuyaqi 发表于 2023-5-17 14:05
显示数目递进不要用for,用定时间隔+1.

感谢！
改用定时器，果然正常显示了
改后代码如下：

#include <reg51.h>
#include <stdio.h>
#define uchar unsigned char
#define uint unsigned int
#define ulong unsigned long
sbit clk = P3^0;
sbit dat = P3^1;
sbit sclk1 = P3^2;
sbit sclk2 = P3^3;
uchar code num[] = {0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};
ulong number;
uchar a = 0;
void delay100us(uint n)
{
uchar i;
for(;n>0;n--)
{
for(i=0;i<10;i++){;}
}
}
void T0_init()
{
TMOD = 0x01;
TH0 = (65536-50000)/256;
TL0 = (65536-50000)%256;
EA = 1;
ET0 = 1;
TR0 = 1;
}
void T0_timer() interrupt 1
{
TH0 = (65536-50000)/256;
TL0 = (65536-50000)%256;
a++;
if(a == 10)
{
++number;
a = 0;
}
if(number == 100000000) number = 0;
}
void data_num(uchar dat8) //串口数据发送数字数据
{
uchar i;
for(i=0;i<8;i++)
{
clk = 0;
dat = (dat8 >> i) & 0x01;
clk = 1;
}
sclk1 = 0;
sclk1 = 1;
}
void digit_num(uchar digit) //串口数据发送LED位数数据
{
uchar i;
for(i=0;i<8;i++)
{
clk = 0;
dat = (digit >> i) & 0x01;
clk = 1;
}
sclk2 = 0;
sclk2 = 1;
}
int digit_check(ulong n) //检测显示目标数的位数
{
uchar m;
if(n>9999999)
m = 8;
else if(n>999999)
m = 7;
else if(n>99999)
m = 6;
else if(n>9999)
m = 5;
else if(n>999)
m = 4;
else if(n>99)
m = 3;
else if(n>9)
m = 2;
else
m = 1;
return m;
}
int main(void)
{
ulong n;
uint i,m;
number = 0;
T0_init();
while(1)
{
m = digit_check(number);
n = number;
for(i=0;i<m;i++)
{
data_num(0xff);
digit_num(0x01 << i);
data_num(num[n%10]);
//delay100us(100);
n = n/10;
}
}
}

复制代码

ID:647261 · 发表于 2023-5-18 09:09

wulin 发表于 2023-5-17 15:02

这个好，省一个IO口，代码看起来也更短

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