一个定时器实现3个两位数码管倒数计时

ID:97948 · 发表于 2016-7-8 14:08

#include <reg51.h>
#define uchar unsigned char
uchar code Table[]=  {0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f};
uchar num3,num4,ge1,shi1,num1,num2,ge,shi,num5,num6,ge2,shi2;
void delay()
{
   uchar i,j;
for(i=40;i>0;i--)
for(j=110;j>0;j--);
}
void T0_time() interrupt 1
{
TH0=(65535-45872)/256;
TL0=(65535-45872)%256;

num1++;
      num3++;
      num5++;

if(num1==20)
{
num1=0;
num2--;

if(num2==0)
   num2=45;

}

if(num3==20)
{
num3=0;
num4--;
if(num4==0)
   num4=65;

}
if(num5==20)
{
num5=0;
num6--;
if(num6==0)
   num6=76;

}
}
void display(uchar ge,uchar shi )
{
      shi=num2/10;
      ge=num2%10;
      P2=0xfd;

      P0=Table[ge]; delay();
      P2=0xfe;
      P0=Table[shi];  delay();
      }

void display1(uchar ge1,uchar shi1)
      {
      shi1=num4/10;
      ge1=num4%10;

      P2=0xf7;
      P0=Table[ge1]; delay();
      P2=0xfb;
      P0=Table[shi1];  delay();
      }

void display2(uchar ge2,uchar shi2)
      {
      shi2=num6/10;
      ge2=num6%10;

      P2=0xdf;
      P0=Table[ge2]; delay();
      P2=0xef;
      P0=Table[shi2];  delay();
   }

void main()
{
TMOD=0x01;
TH0=(65535-45872)/256;
TL0=(65535-45872)%256;
EA=1;
ET0=1;
TR0=1;
num1=0;num2=45;
   num3=0; num4=65;
num5=0;num6=76;

while(1)
{
   display(ge,shi);
display1(ge1,shi1);
   display2(ge2,shi2);

  }
  }

ID:36359 · 发表于 2016-7-15 22:26

老大呀原理图怎么没有啊？

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