16*16汉字点陈，多个汉字怎么一个接一个显示出来？

ID:219908 · 发表于 2017-7-15 16:39

#include<reg51.h>
#include<intrins.h>

typedef unsigned char u8;
typedef unsigned int u16;

void delay(u16 i)
{
while(i--);
}

u8  code ledwei[]=
{
  0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
  0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x02,0x04,0x08,0x10,0x20,0x40,0x80,

};

sbit  SER = P3^4; //串行数据输入
sbit  RCLK = P3^5; //存储寄存器时钟输入
sbit  SRCLK = P3^6; //移位寄存器时钟输入

u8 code Digital1[]=
{
/*--  文字:  普  --*/
/*--  宋体12;  此字体下对应的点阵为：宽x高=16x16 --*/
0x40,0x44,0x54,0x64,0x45,0x7E,0x44,0x44,0x44,0x7E,0x45,0x64,0x54,0x44,0x40,0x00,
0x00,0x00,0x00,0xFF,0x49,0x49,0x49,0x49,0x49,0x49,0x49,0xFF,0x00,0x00,0x00,0x00,

};

u8 code Digital2[]=
{
/*--  文字:  我  --*/
/*--  宋体12;  此字体下对应的点阵为：宽x高=16x16 --*/
0x20,0x24,0x24,0x24,0xFE,0x23,0x22,0x20,0x20,0xFF,0x20,0x22,0x2C,0xA0,0x20,0x00,
0x00,0x08,0x48,0x84,0x7F,0x02,0x41,0x40,0x20,0x13,0x0C,0x14,0x22,0x41,0xF8,0x00,

};

void HC595(u8 dat1,u8 dat2, u8 dat3, u8 dat4)
{
u8 a;

for(a=0; a<8; a++)
{
   SER = dat1 >>7;
   dat1 <<= 1;

   SRCLK = 0;
   _nop_();
   _nop_();
   SRCLK = 1;
   _nop_();
   _nop_();

}

for(a=0; a<8; a++)
{
   SER = dat2 >>7;
   dat2 <<= 1;

   SRCLK = 0;
   _nop_();
   _nop_();
   SRCLK = 1;
   _nop_();
   _nop_();

}

for(a=0; a<8; a++)
{
   SER = dat3 >>7;
   dat3 <<= 1;

   SRCLK = 0;
   _nop_();
   _nop_();
   SRCLK = 1;
   _nop_();
   _nop_();

}

for(a=0; a<8; a++)
{
   SER = dat4 >>7;
   dat4 <<= 1;

   SRCLK = 0;
   _nop_();
   _nop_();
   SRCLK = 1;
   _nop_();
   _nop_();

}

   RCLK = 0;
   _nop_();
   _nop_();
   RCLK = 1;
   _nop_();
   _nop_();

}

void main()
{
u8 i ;

while(1)
{
   for(i=0;i<16;i++)
   {
      HC595(~ledwei[i+16],~ledwei[i],Digital2[16+i],Digital2[i]);
   delay(10);

   }

}
}

ID:219796 · 发表于 2017-7-15 19:21

用二维数组，譬如woshi[][]={{我}；{是}}我和是是点阵数组

ID:21069 · 发表于 2019-2-3 01:45

不难,建议在论坛找一个现实的案例调试,先开懂代码,再改改修修,后自己写整个代码就掌握了

ID:474631 · 发表于 2019-2-3 22:52

二维数组你看看main里面的循环吧
#include "reg51.h"
#include "intrins.h"
typedef unsigned char u8;
typedef unsigned int u16;
#define WEI P0
sbit shcp=P3^6;
sbit stcp=P3^5;
sbit ds=P3^4;
u8 Weixuan[8]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};
u8 Word[4][8]={{0x8a,0x7e,0x2a,0x9f,0xd5,0xff,0xd5,0x9f},
            {0x40,0x44,0x44,0x7c,0x44,0x44,0x40,0x00},
            {0x88,0x48,0x28,0x1e,0x28,0x48,0x88,0x00},
{0x06,0x22,0x2b,0xaa,0xfb,0x2a,0x23,0x06}};
void delay(u16 i)
{
while(i--);
}
void SendData(u8 dat)
{
u8 i;
shcp=0;stcp=0;
for(i=0;i++;i<8)
  {
ds=dat>>7;
dat<<=1;
shcp=1;//上升沿时数据移位
_nop_();
_nop_();
shcp=0;
}
stcp=1;//移动结束后产生正脉冲所以是在循环外上升沿
_nop_();
_nop_();
stcp=0;
}
void main()
{
u8 i,j=0;

u16 a=0;
while(1)
{

for(i=0;i<8;i++)
{
WEI=Weixuan[i];
SendData(Word[j][i]);
delay(2);SendData(0x00);
}
a++;
j++;
if(j==4)
j=0;
}
}

ID:472268 · 发表于 2019-2-12 01:30

用二维数组

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16*16汉字点陈，多个汉字怎么一个接一个显示出来？

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