把case(1)里面改成LSA=0;LSB=0;LSC=1;之后数码管第二个不亮了怎么回事?
- #include<reg52.h>
- typedef unsigned char u8;
- typedef unsigned int u16;
- sbit LSA=P2^2;
- sbit LSB=P2^3;
- sbit LSC=P2^4;
- u8 code smgduan[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71,0x00};
- void delay(u16 i)
- {
- while(i--);
- }
- void DigDisplay()
- {
- u8 i;
- for(i=0;i<8;i++)
- {
- switch(i)
- {
- case(0):
- LSA=0;LSB=0;LSC=0;break;
- case(1):
- LSA=0;LSB=0;LSC=1;break;
- case(2):
- LSA=0;LSB=1;LSC=0;break;
- case(3):
- LSA=1;LSB=1;LSC=0;break;
- case(4):
- LSA=0;LSB=0;LSC=1;break;
- case(5):
- LSA=1;LSB=0;LSC=1;break;
- case(6):
- LSA=0;LSB=1;LSC=1;break;
- case(7):
- LSA=1;LSB=1;LSC=1;break;
- }
- P0=smgduan[i];
- delay(100);
- P0=0x00;
- }
- }
- void main()
- {
- while(1)
- {
- DigDisplay();
- }
- }
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